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Physics 11 Online
OpenStudy (anonymous):

A particle moves along the x axis according to the equation x = 6t2, where x is in meters and t is in seconds. Therefore: A. the acceleration of the particle is 6 m/s2 B. t cannot be negative C. the particle follows a parabolic path D. each second the velocity of the particle changes by 9.8 m/s E. none of the above PLZZ ANYONE CAN EXPLAIN

OpenStudy (abhisar):

Hello @aghast ! \(\boxed{\boxed{\boxed{\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}\\\color{white}{.}\\\Huge\color{blue}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}\\\color{white}{.}\\\\\Huge{\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}\color{orange}{\bigstar}\color{red}{\bigstar}\color{blue}{\bigstar}\color{green}{\bigstar}\color{yellow}{\bigstar}}}}}\)

OpenStudy (abhisar):

accelaration of the particle will be 12 m/s^2

OpenStudy (abhisar):

I think t cannot be negative will be the answer, since t cannot be negative unless untill stated in relative

OpenStudy (anonymous):

since it is given x-6t2,it gives the displacement.Acceleration is the 2nd order derivative of distance. \[d ^{2}y/ dt ^{2} (6t ^{2})=12\]

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