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In solving a rational equation, you find that the solutions are 5 and –2. However, –2 is an extraneous solution. Why would this be the case?
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an extraneous solution is a solution which doesnt work in the original equation
it often occurs in radical equations look at this link for an example http://facstaff.gpc.edu/~tlamar2/10.6radicals.pdf
A. There can only be one solution. B. The denominator of one or more of the expressions would be zero. C. The solution must be positive for the expressions to be rational. D. One or more of the expressions would be zero. here are my choices
A rational equation is a fraction equal to a constant. Why would this fraction return an extraneous solution?
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