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\(y=x^2+6x-1\) in vertex form and do you get it
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do you know what is a "perfect square trinomial"? or often called just a perfect square
If you have a quadratic equation of the form \(y = ax^2 + bx + c\), you can convert it to vertex form by performing the following steps: 1. Note the value of a 2. Find the vertex (h,k) 3. Insert the values of \(a\) and \((h,k)\) in to the vertex formula \(y = a(x - h)^2 + k\).
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