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if f(x) = (2-x)^2 and the y-intercept of f(x) = 4/3, find the rule for f(x)
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rule?
?
Please rewrite the question exactly as asked. @a5657371
that is the question
the question does not make sense.
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okay, thanks for trying-(its a modelling and problem solving question)
since \(f(x)=(2-x)^2\), and the y-intercept is the point \((x,y)\) when \(x = 0\) we see \(f(0)=(2-0)^2=4\) so the y-intercept is \((0,4)\). Having said that, the rest of the question makes no sense either.
Thanks
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