Question

A trig question....Easy for sure...
But it's not clicking my mind...:'(

Just guide me out..8)

Answer 1

Go aheeeeeeeeeeeeeeeeeaaaaaaaaaaaaaaaaad!

Answer 2

whats the question?

Answer 3

First of all sorry for leaving..... My lappy ran out of battery and an auto-matic shut down occured..

Well. here youu go with the question....

Prove that
tan5A + tan 3A divided by tan 5A - tan3A
is equal to 4cos2A.Cos4A

P.S. use Product Formulae of cos and sin for solving the question

Answer 4

@ParthKohli @mathslover @ganeshie8 @dan815 @Compassionate

Answer 5

hmm

Answer 6

multiply top and bottom by conjugate

Answer 7

tan 5A + tan3A *(tan 5A + tan3A )
-------------
tan 5A - tan3A (tan 5A + tan3A )

Answer 8

how will that simplify?

Answer 9

Well.. then we'd get
Tan^2 and to simplify it using product formulas would be difficult...
I mean...rationalizing the denominator would only create a problem for us..!

I already tried that ways...!

Answer 10

yep.. i think i got it.. 2 minute ruko.

Answer 11

Why not..!

Answer 12

IDENTITIES USED:

1) sin(2A) = 2cos(A)sin(A)

so,

sin(4A) = 2cos(2A)sin(2A)

2) sin(A)cos(B) + cos(A) sin(B) = sin(A+B)

and sin(A) cos(B) - cos(A) sin(B) = sin(A-B)

Answer 13

ok nice :)

Answer 14

:-)

Answer 15

What the hell was I thinking of while solving for it ? :p
Anyways... Thank you :)
@dan815 and @mathslover .. .:)

Answer 16

Haha! yeah, it happens. :-)

Good Luck.

Answer 17

Thanks..!
Tu AKS mein mat hi ana...Kush..!
Bada khoon chustey hain teaches... :'(

Answer 18

lol! aane ki planning toh nahin hai, but aisa kya kar diya teachers ne?

Answer 19

Homework hi homework...

Aur tu kuchh aata hi nhi... unko

Answer 20

koi nahin, agar koi problem ho toh mujhe bata dena.. i will try to help. :)

Answer 21

8)