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Please help!!! Parabola passes through (5,2), has a vertical axis, and has a maximum at (4,3). Write the equation.
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@dan815
Standard form for parabola is (x-h)^2=4p(y-k)
@Hero
since the maximum is still a point on the line im thinking can i use it as an x,y coordinate?
Guess what is this maximum point !
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is it the vertex? h,k?
Yes so now you need to fin p only.
*find
Given point should satisfy that equation. Find p from there
ok im not too sure about finding p...
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wait...
i have (x-4)^2=4p(y-3) so p is -1 right? because if i plug in the (5,2) i get 1=-1p divide by -1 to both sides i get -1
yes
Right
yay! thanks!
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