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a^2=2a find a
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\[\large{a^2 = 2a}\] \[\large{\implies a^2 -2a = 0}\] \[\large{\implies a(a-2) = 0}\] \[\large{ a = 0 ~~\text{or}~~ a = 2}\]
a=0,2
a^2-2a=0 a(a-2)=0
a=2,0
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See @manojji; If we have : \[\large{xy = 0}\] Then, it means either x = 0 or y = 0. Now, first I factorised the given expression into product of two expressions, so that I can solve it more easily.
For example, lets see another one: \[\large{a^2 = 3a - 2}\] Can you solve this one ?
\[a ^{2}-2a-a+2\] (a-2) (a-1) helped
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