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Mathematics 17 Online
OpenStudy (anonymous):

Simplify: thirty-two times k plus 8 times k minus fifteen times j minus twenty-eight times k plus 6 times j minus twenty-one times j

OpenStudy (anonymous):

\(32k+8k-15j-28k+6j-21j?\) is it like this??

OpenStudy (anonymous):

yah

OpenStudy (anonymous):

alright. so you have to combine all the terms that have the same variables (all the terms that has j's and all the term that has k's). \(2k+8k−28k−15j+6j−21j\) rearranged it first. then add the terms that have same variables

OpenStudy (anonymous):

what will you end up with?

OpenStudy (anonymous):

do u mean add 32k

OpenStudy (anonymous):

oh yeah, sorry

OpenStudy (anonymous):

it is okay i am working it out now

OpenStudy (anonymous):

on it

OpenStudy (anonymous):

for the k's i got 68 and for the j's i got 42

OpenStudy (anonymous):

remember about the "-" signs , which means subtract.

OpenStudy (anonymous):

18

OpenStudy (anonymous):

nope. can you solve for these: 32+8-28= ? k -15+6-21= ? j

OpenStudy (anonymous):

12

OpenStudy (anonymous):

right for the first one is \(12 k\) . how about the second one?

OpenStudy (anonymous):

0

OpenStudy (anonymous):

30

OpenStudy (anonymous):

nope. try again. take note about "-15"

OpenStudy (anonymous):

0

OpenStudy (anonymous):

nope. it will be -30 j therefore you'll end up with: \(12k-30j\)

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