Question

Use the pythangoream therom to answers these questions! For a medal and fan! A^2+b^2=c^2

Answer 1

@jim_thompson5910

Answer 2

@precal

Answer 3

@zepdrix

Answer 4

\[\Large\rm \color{royalblue}{a=5},\qquad\qquad \color{orangered}{b=12}\]
\[\Large\rm \color{royalblue}{a}^2+\color{orangered}{b}^2=c^2\]\[\Large\rm \color{royalblue}{5}^2+\color{orangered}{12}^2=c^2\]Solve for c! :)
Square the stuff, add it up, then square root each side.

Answer 5

I am so confused!

Answer 6

i got 25+144=169^2

Answer 7

no no it should be 25+144=13^2

Answer 8

i forgot to square it

Answer 9

so i get 25+144=169

Answer 10

Good. so \(\Large\rm 169=c^2\)

Answer 11

ok i get it how about the secound one!

Answer 12

\[\Large\rm \color{royalblue}{5}^2+\color{orangered}{12}^2=c^2\]\[\Large\rm 25+144=c^2\]\[\Large\rm 169=c^2\]\[\Large\rm ?=c\]

Answer 13

Got it? Ok good :)

Hmm is the second one a right triangle?

Answer 14

@sweetburger is that Nicholas Cage on that bunny? 0_o

Answer 15

yeah! sorry i couldn't shape it!

Answer 16

The longest side of the triangle is always our C.
So that means the 14 is our c value.

Answer 17

\[\Large\rm \color{orangered}{b=11},\qquad\qquad \color{green}{c=14}\]
\[\Large\rm a^2+\color{orangered}{b}^2=\color{green}{c}^2\]\[\Large\rm a^2+\color{orangered}{11}^2=\color{green}{14}^2\]This one requires just a little bit more work to solve.

Answer 18

so i got a^2+121=196

Answer 19

Mmmmmk good!
So how do we get a^2 alone?
Gotta deal with that 121.

Answer 20

subtract!

Answer 21

cool c:

Answer 22

a^2=75

Answer 23

\[\Large\rm a^2=75\]\[\Large\rm a=?\]k good, what's your last step then? :o

Answer 24

75 squatred is

Answer 25

squatred? XD

Answer 26

that sounds spanish

Answer 27

squared

Answer 28

is it 9

Answer 29

Not squared. Square root.

Answer 30

8.66025403784

Answer 31

ya c:

Answer 32

thats what on my caculator!

Answer 33

so its 8.66

Answer 34

so could you help me with one more problem!

Answer 35

Yes 8.66.
But if they want an exact answer, you would leave it as \(\Large\rm \sqrt{75}\) or simplify it to \(\Large\rm 5\sqrt3\)

Answer 36

sure

Answer 37

ok find the area and perimeter for the figure below!

Answer 38

Let's label all of the sides.

Answer 39

Perimeter is the distance around the object.
So we just add up all of the side lengths.

Answer 40

\[\Large\rm 3x+3x+~x+2~+~x+2~\]Combine like-terms.

Answer 41

6x^2+x+4

Answer 42

No no no silly.