Question

-a^2-3b^3+c^2+2b^3-c^2 If a=3,b=2, and c=-3

Answer 1

medal?

Answer 2

plug in 3 for a, 2 for b, and -3 for c
into -a^2 - 3b^3 + c^2 + 2b^3 - c^2
so -(3)^3 - 3(2)^3 + (-3)^2 + 2(2)^3 - (-3)^2
simplfiy

Answer 3

Is the answer 55?

Answer 4

not quite :)
-(3)^3 - 3(2)^3 + (-3)^2 + 2(2)^3 - (-3)^2 becomes
-27 - 24 + 9 + 16 - 9

Answer 5

Thank You So Much

Answer 6

You're welcome :)