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Mathematics 7 Online
OpenStudy (anonymous):

Can someone please check my work?

OpenStudy (marissalovescats):

What is it?

OpenStudy (anonymous):

just a sec, im posting it...

OpenStudy (marissalovescats):

Alrighty

OpenStudy (anonymous):

\[9x ^{2}-4y ^{^{2}}-54x-40y-55=0\] \[\frac{ (x-3^{2}) }{ 4 }-\frac{ (y-5)^{2} }{ -9 }=1\] Standard form so center is (3,5)

OpenStudy (vishweshshrimali5):

I think thats (x-3)^2 ?

OpenStudy (anonymous):

yes, sorry typo

OpenStudy (vishweshshrimali5):

Also, why did you write -9 in denominator ?

OpenStudy (anonymous):

because i got 36/-4 i need to find the foci,vertices, and retricemptotes

OpenStudy (anonymous):

*retricemptotes

OpenStudy (anonymous):

why wont it let me write retricemptotes?

OpenStudy (vishweshshrimali5):

First of all I would suggest you to check your work again.

OpenStudy (anonymous):

(asymptotes)

OpenStudy (vishweshshrimali5):

I think that should be 9 in denominator.

OpenStudy (anonymous):

ok i think i just saw that as a -4 not minus 4

OpenStudy (vishweshshrimali5):

So, did you get your mistake?

OpenStudy (anonymous):

yep, can you help me find the foci, vertices, and asymptotes?

OpenStudy (vishweshshrimali5):

Yeah sure. Whats your approach ?

OpenStudy (anonymous):

well since a is under the y^2 i need to use (h, k+c) (h,k-c) to find the foci, right?

OpenStudy (anonymous):

so is thats: \[(3, 5+\sqrt{13}) (3,5-\sqrt{13})\]

OpenStudy (vishweshshrimali5):

Just a minute let me check it

OpenStudy (vishweshshrimali5):

No that's wring

OpenStudy (vishweshshrimali5):

I would suggest you to go through this link http://calculator.tutorvista.com/hyperbola-calculator.html

OpenStudy (anonymous):

thanks

OpenStudy (vishweshshrimali5):

np

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