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3x^2-3y^2
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exponets
what's the question??
factor it
well, take 3 common, that will be 3(x^2-y^2) now you have to see if you can factorise (x^2-y^2) as you know, (x+y)(x-y)= x^2-y^2 [REMEMBER THIS FORMULA] then 3(x^2-y^2)=3(x+y)(x-y)
I got it right thnc
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