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For this right triangle determine cos(90-theta)
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have you covered the sum/difference trigonometric identities yet?
nope im in algebra 2
well let's take a look at the triangle|dw:1403213872711:dw| recall that all internal angles in a right triangle add up to 180 degrees so that means \(\bf \theta+{\color{brown}{ \beta}}+90=180\implies \theta+{\color{brown}{ \beta}}=90\implies {\color{brown}{ \beta}}=90-\theta\qquad thus \\ \quad \\ cos(90-\theta) \iff cos({\color{brown}{ \beta}})\to \cfrac{adjacent\ side}{hypotenuse}\to \cfrac{a}{c}\)
hmmm actaully the adjacent is "b" one sec... so |dw:1403214263480:dw|
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