Question

Question in attachment

Answer 1

@Loser66

Answer 2

@IMStuck

Answer 3

step by step please

Answer 4

a) initial value is when h =0 , replace to the equation, what do you get?

Answer 5

105.26

Answer 6

??

Answer 7

how to get it?

Answer 8

replacing 0 with h

Answer 9

so? \[P(0) = \dfrac{200}{0.9+0.1e^0}=\dfrac{200}{1}=200\] how can you get 105.26??

Answer 10

My calculator is messed up

Answer 11

ok, for b) the number of parasite is half mean P = 100, right? replace it into the equation to solve for h

Answer 12

ok let me do it

Answer 13

@dumbcow Please, help. I don't know how to do part c

Answer 14

is it 2?

Answer 15

I dont know how to rearrange it properly

Answer 16

@Loser66

Answer 17

ok but lets finish part b first

first divide by 200
then take reciprocal of both sides
\[\rightarrow 2 = 0.9 + 0.1e^{2h}\]

Answer 18

okay and then?

Answer 19

can you solve for e^2h

Answer 20

im stuck there

Answer 21

by the way, is this for calculus?

Answer 22

yeah

Answer 23

can you help?

Answer 24

you should be able to do the algebra then... can you solve this

4 + 6x = 10

Answer 25

x=1

Answer 26

right so apply same thing to
\[.9 + .1 e^{2h} = 2\]

Answer 27

go to wolfram and figure it out. good bye

Answer 28

how do you part c ?

Answer 29

@dumbcow