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Mathematics 11 Online
OpenStudy (anonymous):

how do you do this

OpenStudy (anonymous):

\[(6+3\sqrt{2})(5-\sqrt{2)}\]

OpenStudy (anonymous):

expand:)

OpenStudy (anonymous):

FOIL it

OpenStudy (anonymous):

OpenStudy (anonymous):

\[(6+3\sqrt{2})(5-\sqrt{2})=6\times 5-6\times \sqrt2+15\sqrt2-3\times (\sqrt2)^2\] is a start

OpenStudy (anonymous):

combine like terms for the middle two, and note that \(\sqrt2^2=2\) so the last term is actually \(-6\)

OpenStudy (anonymous):

i dont know what to do

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