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Solve and write your solution in interval notation..\[-3\le2x-1<5\]
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-2 <= 2x < 6 -1 <= x < 3
1) add \(1\) all the way across 2) divide everything by \(2\)
^ what the bicycle said
I got \[-3\le2x-1<5=-3+1\le2x+1<5+1=-4\le2x <6 =-2lex <3\]
A little mistake, -3 + 1 = -2...you wrote -4
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Oops..yes you are right@ Cormacpayne
how do I write it in interval notation? \[(-1,3\right]\]
lol \[[-1,3)\] i think is what you meant
^ that
which is the same as -1 <= x < 3
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