Question

Find 3 consecutive even numbers where the product of the smaller two numbers is 64 less than the square of the largest number.

Answer 1

let first number be x
second will be x+1
third will be x+2

Answer 2

now product of smaller numbers is 64 less than square of largest number
so you get x(x+1) = (x+2)^2 -64
now solve for x

Answer 3

I just learned that the variable has to be added x+2 to be evemn

Answer 4

even*

Answer 5

there i gave you the equation ^

Answer 6

@dan815

Answer 7

Wrong equation

Answer 8

x will be the 1st number
x+2 second number
x+4 3rd number

Answer 9

x,x+2,x+4
my bad
its x(x+2) = (x+4)^2- 64

Answer 10

apologies,didnt see the even thing

Answer 11

(x)(x+2) = (x+4)^2- 64

simplify them and you have,
x^2+2x = x^2 + 8x + 16 - 64

Answer 12

x = 8

Answer 13

8,10,12. Thanks guys, I appreciate it.

Answer 14

yes, you're welcome