Question

Find 3 consecutive odd numbers where the product of the smaller two numbers is 22 less than the square of the largest number.

Answer 1

@sid0830

Answer 2

Let the first number = 2x + 1
The seconds is 2x + 3
The third is 2x + 5

The product of the 2 smaller numbers is 22 less than the square of the third...so we have

\[\large (2x + 1)(2x + 3) = (2x + 5)^2- 22\]

Answer 3

x(x+2)=(x+4)^2-22

Answer 4

\[(x)(x+2)=(x+4)^2−22\]
x=1 ..answer :)

Answer 5

n=1