Question

x+(x^(-1))/(-1)=x+1?

Answer 1

\[\large x + (\frac{x^{-1}}{-1}) = x+1\]

We know x^-1 is just 1/x so we have

\[\large x - \frac{1}{x} = x + 1\]

We want the left side to look like the right side...

we HAVE the x

\[\large \color \red{x} - \frac{1}{x} = \color \red{x} + 1\]

We just need to make

\[\large - \frac{1}{x} = 1\]

Well the only way THAT can happen...is if x = -1

Since

\[\large - \frac{1}{-1} = 1\]

So your answer would be x = -1

Answer 2

\[\frac{ 4x-2 }{ x} =3\]