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Solve the inequality. 26 + 6b >2(3b + 4)
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Where's the inequality? ^_^
lol
26+6b>=6b+8 26>=8 here is something that the others failed to mention: Since 26 is always greater than 8, this would mean that there are an infinite number of solutions!!!!
Yea. Gur.:) That's like using the Distributive Property, to remove the parentheses
There fixed the question haha
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There we go :P alright so we have \[\large 26 + 6b > 2(3b + 4)\] we distribute the 2 through the parenthesis \[\large 26 + 6b > 6b + 8\] which simplifies to \[\large 26 > 8\] Since this is a true statement...this inequality has an infinite number of solutions
So if i were to graph it would i answer it with No solution?
Nvm lol i got thanks :)
anytime :)
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