Factor completely and check mentally

18x^2yz+12xy^2z+6xyz^2

Question

Factor completely and check mentally

18x^2yz+12xy^2z+6xyz^2

dan815 · Answer

6 is common number..
xyz is common as well

anonymous · Answer

6 is common because it's a multiple?

anonymous · Answer

Okay, now what.

dan815 · Answer

okay ill do the middle term this time.. you dothe other 2 terms

anonymous · Answer

Noooo omg don't do anything. I just need to learn HOW to do it.

muzzack · Answer

Step by step solution :

Simplify   $\large\ 18x^2yz+12xy^2z +  (2•3xyz^2)$

Pull out like factors :

$\large\ 18x^2yz + 12xy^2z + 6xyz^2  =   6xyz • (3x + 2y + z)$ 

Final result :

$\huge\ 6xyz • (3x + 2y + z)$

dan815 · Answer

6xyz(_____+_______+_______)
The middle term ^ has to be 12xy^2z
What should you multiply 6xyz by to get 12xy^2z
6xyz * 2 * y = 12xy^2z so... we put
6xyz(_____+__2* y__+_______)

dan815 · Answer

Muzzack explain to him im simpler terms T_T i dont know how

anonymous · Answer

Wait, how did you figure that out?

anonymous · Answer

"What should you multiply 6xyz by to get 12xy^2z
6xyz * 2 * y = 12xy^2z so... we put" that part..

anonymous · Answer

-_-