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At what point on the graph of the function f(x)= square root (3x-2) is the normal line perpendicular to the line defined by the equation y=(1/4)x-3
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I took the derivative of f(x) and am not sure what to do. Should I set that equal to -4 and solve for x
When the normal line is perpendicular to the other line, then the tangent line will be parallel to the other line. In 2D, perpendicular to perpendicular is parallel.
so I should be setting it equal to 1/4 and solving for x?
yes
I got 38/3
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