Question

At what point on the graph of the function f(x)= square root (3x-2) is the normal line perpendicular to the line defined by the equation y=(1/4)x-3

Answer 1

I took the derivative of f(x) and am not sure what to do. Should I set that equal to -4 and solve for x

Answer 2

When the normal line is perpendicular to the other line, then the tangent line will be parallel to the other line.

In 2D, perpendicular to perpendicular is parallel.

Answer 3

so I should be setting it equal to 1/4 and solving for x?

Answer 4

yes

Answer 5

I got 38/3

Answer 6

Thanks