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Calculus1
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Find dy/dx by implicit differentiation. 3x2 + 5xy − y2 = 5
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\(3x^2+5xy-y^2=5\implies 6x+5(y+x*\frac{dy}{dx})-2y\frac{dy}{dx}=0\)
make sense so far?
that middle part is the product rule for \(xy\)
and that last part is the chain rule on \(y^2\)
so we have \(6x+5y+5x\frac{dy}{dx}-2y\frac{dy}{dx}=0\) Now solve for \(\frac{dy}{dx}\)
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