Question

4-x(2x-3)=16

Answer 1

do you know order of operations?

Answer 2

no..

Answer 3

ok have you heard of PEMDAS?

Answer 4

no..sorry..

Answer 5

Ok it basically means that you have to solve equations a certain way. Make sense so far?

Answer 6

ahmm can u teach me?

Answer 7

Alright :) its really easy if you apply yourself. So PEMDAS stands for:
parentheses
exponents
multiplication
division
addition
subtraction

And since your equation is 4-x(2x-3)=16 do you know what your first step would be?

Answer 8

so.. 1x?

Answer 9

Good guess but no. Since the first thing in pemdas is "parentheses" we are going to distribute the x to the (2x-3) which would give us \[2x ^{2}-3x\] Still following me?

Answer 10

yes.. so..1x^2?

Answer 11

where do you get that from?

Answer 12

...
dont know..

Answer 13

Ok well try this. Using what i said earlier about 2x^2-3x let make the revised equation.

Now all we have is \[4-2x^2-3x=16\] then we could move the 4 over to the other side so then it would be this equation
\[-2x^2-3x=12\]
Do you understan?

Answer 14

*understand

Answer 15

it should be quadratic...

Answer 16

Oh yes my apologies, you are correct i seem to have made a mistake here. We could just move the 4 around and get rid of that nasty negative sign which should make it like this \[2x^2+3x+4=-16\]
does this seem correct to you?

Answer 17

it should be ax^2+bx+c=0

Answer 18

Yes i am aware of that i am just going step by step so that you understand what i am doing here. Now that we have 2x^2+3x+4=-16 what do you think would be the next logical step?

Answer 19

sorry dont know...

Answer 20

It would be to do the reciprocal of -16 to get the equation to match the formula. So it would then be
2x^2+3x+20=0 what do you think is next?

Answer 21

a=2
b=3
=20??

Answer 22

Yes you have the values for a and b correct, and im guessing you meant to put c=20? but yes you are correct non the less. Now do you know the quadratic formula?

Answer 23

yes

Answer 24

Sorry i must go now, perhaps @hartnn can further assist you in this problem? I truly am sorry to leave.