Where is the vertex of the parabola?
y = x^2 + 2x – 3

A.

Above the x-axis

B.

Below the x-axis

C.

On the x-axis

D.

On the y-axis

Question

Where is the vertex of the parabola?
y = x^2 + 2x – 3

A. 
 
Above the x-axis
   
   

 

 
  

  B. 
 
Below the x-axis
   
   

 

 
  

  C. 
 
On the x-axis
   
   

 

 
  

  D. 
 
On the y-axis

anonymous · Answer

This is the same thing I just did I think, so use the graphs from the previous question's correct answer.

anonymous · Answer

Previous one was y = 2x^2 + 5x - 3

anonymous · Answer

Oh, well then it's the same concept.

anonymous · Answer

In other words, find the point where the slope is zero.

anonymous · Answer

You can simplify your function if you'd like and locate the two coordinates where the parabola touches on the x-intercept.

anonymous · Answer

For example, y = x^2 + 2x - 3 can be transformed into

y = (x - 1) ( x + 3)

Therefore, the parabola goes through 1 and -3 on the x-intercept.