What is the equation of the line which includes points (2, 6) and (0, 0)? y = -3x + 1 y = -3x y = 3x y = 3x + 1
Is it c?
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 2}}\quad ,&{\color{blue}{ 6}})\quad &({\color{red}{ 0}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\ \qquad \uparrow\\ \textit{point-slope form}\)
is it not 3x?
what did you get for the slope?
3
oh h.. yeap..is 3x
c is correct?
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ 2}}\quad ,&{\color{blue}{ 6}})\quad &({\color{red}{ 0}}\quad ,&{\color{blue}{ 0}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= 3 \\ \quad \\ y-{\color{blue}{ 0}}={\color{green}{ 3}}(x-{\color{red}{ 0}})\implies y=3x\)
so yeap
Thank you:)
yw
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