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Mathematics
3 Online
[Periodic Functions and Applications]
Solve sin^2x=1/4 for 0
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From sin^2x=1/4 So sinx = 1/2 You could continue by looking up for formulas
Hmmm I got that far, then first solution is 30degrees, the second is 150degrees...? There must be something else I am missing, as the textbook lists two other values :S
\[\sin^2 x = 1/4 \implies \sin(x) = \pm 1/2\]
Remember that the square of \(-1/2\)
is also \(1/4.\)
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Ah, so while 30 and 150 degrees are the solutions when sin is positive, having sin^2x means that I must also find solutions when sin is negative?
Indeed.
Okay, thanks for the help!
What did you get for the negative values? And no problem!
210 and 330 degrees
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That is correct.
YES
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