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The equation x-(1/2)=-2(y+4) represents the equation of the tangent line to the graph of g(x) when x=-1. What is the value of g'(-1)?
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put tangent line in "y=mx+b" form, then g'(x)= m since slope of tangent equals derivative
sorry g'(-1)
ok let me do that
I got -3 but it is not listed for my choices
I have -1/2, 4, -2, and 1/2 and can not be determined
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first did you divide by -2 ? --> y+4 = -x/2 +1/4
yes and then I subtracted 4 to both sides
I got y=(-1/2)x-(15/4)
good, now what is the slope?
slope is -1/2 oh is that what they want, man I got to get better at reading these problems
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haha yeah
thanks you are the best
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