The equation x-(1/2)=-2(y+4) represents the equation of the tangent line to the graph of g(x) when x=-1. What is the value of g'(-1)?

Question

The equation x-(1/2)=-2(y+4) represents the equation of the tangent line to the graph of g(x) when x=-1.  What is the value of g'(-1)?

dumbcow · Answer

put tangent line in "y=mx+b" form, then g'(x)= m since slope of tangent equals derivative

dumbcow · Answer

sorry g'(-1)

precal · Answer

ok let me do that

precal · Answer

I got -3 but it is not listed for my choices

precal · Answer

I have -1/2, 4, -2, and 1/2 and can not be determined

dumbcow · Answer

first did you divide by -2 ?

--> y+4 = -x/2 +1/4

precal · Answer

yes and then I subtracted 4 to both sides

precal · Answer

I got y=(-1/2)x-(15/4)

dumbcow · Answer

good, now what is the slope?

precal · Answer

slope is -1/2  oh is that what they want, man I got to get better at reading these problems

dumbcow · Answer

haha yeah

precal · Answer

thanks you are the best