Question

the first phase in normal cellular respiration and the only one occurring in the cytoplasm is called

Answer 1

Glycolysis

Answer 2

do u get it?

Answer 3

Glycolysis - and this will create 2 ATP and 2 Pyruvate as the products of these two, the Pyruvate will then be used in Krebs cycle to break down this molecule further to create more ATP.

Answer 4

anything else?

Answer 5

Agreed. Glycolysis is the first step in cellular respiration for both anaerobic and aerobic processes. Glycolysis takes place in the cytosol of a cell. In the cytosol we convert 1 molecule of glucose into 2 molecules of pyruvate.

Answer 6

Glycolysis but it yields 8 ATP molecules and 2 pyruvic acid, where this pyruvic acid formed will be continued in the kreb's cycle...!!!!!!1

Answer 7

way to go Comet-Girl

Answer 8

@alphadxg
It gives 2 ATP only in anaerobic organisms and 8 ATP in aerobic organisms only and this aerobic organisms will undergo further krebs cycle but not the anaerobic organisms

Answer 9

@deepika.comet I said 2 atp because the question specifically asks for normal respiration..............

Answer 10

yeah but you have mentioned that it further undergoes krebs cycle which is a wrong statement.

this is what you told
Glycolysis - and this will create 2 ATP and 2 Pyruvate as the products of these two, the Pyruvate will then be used in Krebs cycle to break down this molecule further to create more ATP.
i will correct your statement it is not 2 ATP, glycolysis always gives 8ATP not 2ATP..
when 2ATP is released i.e the pyruvate released forms alcohol
but what you told above says that it further undergoes krebs cycle

when 8ATP and pyruvate are released from glycolysis it goes further krebs cycle giving 38 ATP where krebs cycle occurs mitochondria..

Answer 11

you said 2 ATP which is wrong the question says the first cellular respiration that occurs is cytoplasm is sure glysolysis but it never gives 2ATP it always gives 8ATP..

@ALPHADXG