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OpenStudy (anonymous):
How long will it take a population to triple if it is growing at a rate of 2.4% continuously?
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OpenStudy (zzr0ck3r):
what is the equation for continuous growth?
OpenStudy (zzr0ck3r):
hint: pert
OpenStudy (dan815):
xD
OpenStudy (anonymous):
e^0.024t=3 ? is that the equation?
OpenStudy (zzr0ck3r):
well we would have \(A=Pe^{rt} \) but now we want \(Pe^{rt}=3P\)
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OpenStudy (zzr0ck3r):
so \(e^{0.024*t}=3\)
OpenStudy (zzr0ck3r):
can you solve for t?
OpenStudy (anonymous):
You would take the log of e^(0.024)(t) and log of 3?
OpenStudy (anonymous):
then divide the log of 4 by o.o24?
OpenStudy (anonymous):
log of 3*
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OpenStudy (zzr0ck3r):
try this
\(ln\) of both sids
\(ln(e^{0.024t})=ln(3)\\
0.024t*ln(e)=ln(3)\\0.24t*1=ln(3)\\t=\frac{ln(3)}{0.024}\)
OpenStudy (anonymous):
20 years?
OpenStudy (zzr0ck3r):
if you take ln of one side you must do ln of the other, you cant do natural log on one side and log base 3 on the other
OpenStudy (zzr0ck3r):
if thats what that is....
OpenStudy (zzr0ck3r):
I aint no calculator:)
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OpenStudy (anonymous):
Lol :D Let me do it real quick. Pretty sure I did Log not Ln
OpenStudy (anonymous):
Thanks so much ^_^
OpenStudy (zzr0ck3r):
np
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