Question

Describe the differences between the graph of y = -3(x + 7)2 - 10 and the standard position graph of y = x2.

Answer 1

y = mx + b
y = (-3)((x + 7)^2) - (10)

Answer 2

Do you know how to graph this?

Answer 3

yes u find the vertex by this formula x=-b/2a

Answer 4

then u take 2 points away from it

Answer 5

I find it easier to use a function to find two separate points, want me to show you how?

Answer 6

yes

Answer 7

y = -3(x + 7)^2 - 10

y = f(x)

f(x) = -3(x + 7)^2 - 10

Let x = 0

f(0) = -3(0 + 7)^2 - 10
f(0) = -3(7)^2 - 10
f(0) = -3(49) - 10
f(0) = -147 - 10
f(0) = -157

So when x = 0 y = -157
(0,-157)

Also, when x = 0, you have your y intercept when you find y. So the y intercept is -157.

Answer 8

All you have to do is take the equation an plug in any value for x and solve for y. Then you have an ordered pair. You need two ordered pairs to graph it.

Answer 9

ok