Question

Solve for x: e^(2x)-2e^(x)-3=0
So completely lost. Hate natural logarithms. Explanation please?

Answer 1

@SarahEZZMcK

Answer 2

Hint: rewrite as
(e^x)^2 - 2e^x - 3 = 0

Then substitute y for e^x:
y^2 - 2y - 3 = 0

Then factor

Answer 3

Then solve for y and plug that answer into y=e^x?

Answer 4

Solve for y, then replace y with e^x. Afterwards, solve for x.

Answer 5

Factoring leads to (y-3) and (y+1)
sooo.....
(e^x-3)(e^x+1)=0
...... now it looks like I need to put this into logarithmic form.... I think?

Answer 6

no!! hold on....

Answer 7

e^x=3 and e^x=-1
soooo....

Answer 8

Solve for x if possible.

Answer 9

I just revert this into ln form... so... because ln(-1) isn't possible....
the only possible answer is x=ln(3) ?

Answer 10

WOOHOO!! :D Thank you, sir!