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Suppose p varies directly as d, and p = 2 when d = 7. What is the value of d when p = 10? A. d= 20/7 B. d= 7/5 C. d=35 D. d=15
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\(\bf \begin{array}{cccllll} \textit{something }&\textit{varies directly to }&\textit{something else}\\ \quad \\ \textit{something }&={\color{red}{ \textit{some value }}}&\textit{something else}\\ \quad \\ p&={\color{red}{ n}}&d&\implies p={\color{red}{ n}}d \end{array}\\ \quad \\ p=2\qquad d=7\implies p={\color{red}{ n}}d\to 2={\color{red}{ n}}\cdot 7\) solve for "n" to find the "constant of variation" once you find "n", then plug it back in the equation to find "d" when p=10, just set p = 10 and solve for "d"
15?
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