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use the distributive property to remove the parenthesis: (x - 12) 10 =
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(x-12)(10) multiply each value inside (x-12) to 10 to expand.
still confused
ex: (x + 2)(x + 5) = x·x + x·5 + 2·x + 2·5 for this you have ( x - 12 ) ( 10 + 0 ) = x * 10 + x * 0 - 12 * 10 - 12 * 0 = 10x - 120 make sense?
ok so ultimately, i am just multiplying 10 x 12 to come up with my answer
no no, you are multiplying everything inside the paranthese to 10 then adding the products up
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you make it look very easy but clearly this subject is not simple to me..:-)
so what if it is an additon problem like: 10 (3 + x)? do i still add even if the ones within the parenthesis?
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