HELP PLEASE!! The equation of line AB is y = 2x + 4. Write an equation of a line parallel to line AB in slope-intercept form that contains point (3, −2). Answers: y = 2x + 4 y = negative 1 over 2x − 1 over 2 y = − 1 over 2x − 7 over 2 y = 2x − 8
step one find the slope (with your eyeballs) of \( y = 2x + 4\)
2x?
well close, it is the number \(2\) without the variable
oh ok well 2
step 2 know that a parallel line has the same slope, so the slope of the line you are looking for is also \(2\)
so that leaves us with only answers a & b?
step3 write the points slope formula \(y-y_1=m(x-x_1)\) with \[m=2,x_1=3,y_1=-2\]
actually leaves A and D right?
yes my mistake hold on im solving it now!
k
y-2=2(x-3), so y-2= 2x-6
careful here
oh now i add the 2 to the other side to cancel it out
\(y_1=-2\) so \[y-y_1=y+2\] on the left
so y=2x-8?
yes
thank you!
yw hope it is more or less clear
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