What are the x-coordinates of the solutions to this system of equations?

x2 + y2 = 16
y = x + 4

-4 and 0

4 and 0

-2 and -3

2 and -3

Question

What are the x-coordinates of the solutions to this system of equations?

x2 + y2 = 16
y = x + 4

 -4 and 0

 4 and 0

 -2 and -3

 2 and -3

imstuck · Answer

Do you know how to use either the substitution method or the addition method to solve systems of equations?

yanasidlinskiy · Answer

I have a question. Is that ^ $$x^2$$

anonymous · Answer

solve $$x^2+\left( x+4 \right)^2=16~for~x$$

anonymous · Answer

yes @YanaSidlinskiy

anonymous · Answer

and i do know substitution method @IMStuck

imstuck · Answer

In the second equation you are told that y = x + y.  You sub that y in into the first equation to eliminate the y and put the whole equation in terms of x, like this.$$x ^{2}+(x+4)^{2}=16$$Here's the substitution method!

imstuck · Answer

Actually you couldn't use the addition method here anyway because of the unlike x and y terms; one equation has them squared while the other does not.  So any ideas on how to solve what I posted above?

anonymous · Answer

$$\left( a+b \right)^2=a^2+b^2+2*a*b$$