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OpenStudy (anonymous):
Factor. Check by multiplying factors Medal rewarded
8x^3+2x^2+12x+3
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OpenStudy (anonymous):
@JungHyunRan
OpenStudy (anonymous):
@hartnn @Law&Order
hartnn (hartnn):
8x^3+2x^2
factor out 2x^2 from those 2 terms, what do u get ?
OpenStudy (anonymous):
4x^2
hartnn (hartnn):
what, how ?
\(\Large 8x^2 +2x^2 = 2x^2\times 4x +2x^2 = 2x^2 (4x+1) \)
got this ?
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OpenStudy (anonymous):
Oh I see what you did there.
hartnn (hartnn):
now factor out 3 from
12x+3
OpenStudy (anonymous):
4x
hartnn (hartnn):
example of factoring :
\(\large ☻☺+☻♥= ☻(☺+♥) \\ \text{this is factoring, } \\ ☻\text{ was common from both terms and factored out.}\)
hartnn (hartnn):
just 4x ?
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hartnn (hartnn):
\(\Large 12x+3 =3\times 4x+3 = 3 (4x+1)\)
OpenStudy (anonymous):
OH +3. Okay.
hartnn (hartnn):
now you have
\(\Large 2x^2 (4x+1)+3(4x+1)\)
what do u get when you factor out 4x+1 ??
OpenStudy (anonymous):
(2x^2+3)(4x+1)
hartnn (hartnn):
\(\huge \color{red}{\checkmark \quad \ddot \smile}\)
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hartnn (hartnn):
can you verify your answer by multiplying these factors? or need help with that too ?
hartnn (hartnn):
you should again get 8x^3+2x^2+12x+3 from (2x^2+3)(4x+1)
OpenStudy (anonymous):
2x^2(4x+1) 8x^2+2x^2
OpenStudy (anonymous):
Yeah all that lol I got it, Thanks alot man!
hartnn (hartnn):
welcome ^_^
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