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Mathematics 13 Online
OpenStudy (anonymous):

Solve. x2 - 2x = 3.

OpenStudy (skullpatrol):

Any ideas?

OpenStudy (skullpatrol):

$$\Huge x^2 - 2x = 3$$

OpenStudy (anonymous):

would you set it to 0

OpenStudy (skullpatrol):

Sort of. But the idea is to subtract 3 from both sides first.

OpenStudy (anonymous):

oh

OpenStudy (skullpatrol):

$$\Huge x^2 - 2x - 3=0$$

OpenStudy (anonymous):

what would you do next

OpenStudy (skullpatrol):

Factor the left hand side.

OpenStudy (anonymous):

gcf?

OpenStudy (anonymous):

im lost

OpenStudy (skullpatrol):

Nope, not the gcf. Look for two factors of -3 that have opposite signs and add up to -2.

OpenStudy (anonymous):

oh yeah i knda remember now..... -3,1

OpenStudy (skullpatrol):

Yes, so the factorization will look like $$\Huge(x-3)(x+1)=0$$

OpenStudy (anonymous):

the answer is -3,1?

OpenStudy (skullpatrol):

No the answer is not -3, 1. What values of x will make this equation true?

OpenStudy (anonymous):

x=-3 x=1? idk

OpenStudy (skullpatrol):

what is zero times any number?

OpenStudy (anonymous):

0

OpenStudy (skullpatrol):

what value of x in x - 3 will make it 0?

OpenStudy (anonymous):

0?

OpenStudy (skullpatrol):

is 0 - 3 = 0?

OpenStudy (anonymous):

no

OpenStudy (skullpatrol):

if x = 3 then x - 3 becomes 3 - 3 = 0

OpenStudy (anonymous):

ohh i see

OpenStudy (skullpatrol):

and if x = -1 the other factor becomes 0

OpenStudy (skullpatrol):

So the solution set is {3, -1}

OpenStudy (anonymous):

thank you ,, ive got another question

OpenStudy (anonymous):

well its not really a math question

OpenStudy (anonymous):

ive got a final coming up this week thats worth 275(20%) ...it has 36 multiple choice and 4 free response.. i have to get a 60% on the final or i dont get credit for the class. how many questions do you think i would have to get right to get a 60%

OpenStudy (skullpatrol):

You need to get at least 24 question right.

OpenStudy (anonymous):

oh , im screwed

OpenStudy (anonymous):

thanks

OpenStudy (skullpatrol):

thanks for asking :)

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