Question

initial value problem
dy/dx=x^2+1/x^2, y(1)=-1

Answer 1

Did you really mean \(x^{2} + \dfrac{1}{x^{2}}\)

Answer 2

nope (x^2+1)/x^2

Answer 3

\[(x^2+1)/x^2\]

Answer 4

you just need to take the integral

Answer 5

Parentheses are beautiful things.