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-10 + sqrt x+8= -4 can someone take me step by step on how to solve this ?
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\(\bf -10 + \sqrt{x}+8= -4 \qquad\qquad {\color{brown}{ +10\ and -8}} \\ \quad \\ \cancel{ -10 {\color{brown}{ +10}} }+ \sqrt{x}\cancel{ +8{\color{brown}{ -8}} }= -4{\color{brown}{ +10}}{\color{brown}{ -8}}\implies \sqrt{x}=-2\qquad \qquad {\color{brown}{ ^2}} \\ \quad \\ (\sqrt{x})^{\color{brown}{ 2}}=(-2)^{\color{brown}{ 2}}\implies x=+4\)
the sqrt goes over both the x and the 8
then is the same thing... you 'd just add +10 only then and then square both sides
the idea is just to isolate the root on the left-hand-side then square both sides
oh okay thanks
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