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so do i! :D
What is the solution of \[\frac{ 1 }{2 }x-8=-\frac{ 3 }{ 2 }x+2\] A. x = -10 B. x = -3 C. x = 5 D. x = 10
multiply both sides by "2" then simplify
this is easy :'(
I got A
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i think it's correct
hmm how did you get 10 anyway?
ohh it's c
i thought you wrote C lol
I simplified wrong
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woops not even that..lemme fix that
\(\bf \cfrac{ 1 }{2 }x-8=-\cfrac{ 3 }{ 2 }x+2\qquad {\color{brown}{ \times 2}} \\ \quad \\ x-16=-3x+4\implies 4x=20\implies x=5\)
\(\bf \cancel{ 2 }\times \cfrac{1}{\cancel{ 2 }}x\qquad \qquad \cancel{ 2 }\times -\cfrac{3}{\cancel{ 2 }}x\) thus
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