Which of the following situations cannot be modeled with the equation 2x + y = 0? A. It takes 2 parts of chemical A to neutralize 1 part of chemical B. B. Tony must pull twice as hard as Ralph just to sit still in a match of tug-o-war. C. If Sophie earns twice as many points as penalties, she will break even. D. Tom’s Saturday shift was twice as long as his 2 hour Sunday shift.
@mathstudent55
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As you can see your expression is equal to 0 so you must see which one of your situations does not equal 0.
is it c
If Sophie earns 2 x points as Penalties she will "break even" if we set points as A and penalties as B and breaking even as 0. 2A+1B = 0 so it does apply
so i was right!?(:
thank you thank you!
No it was not C
C applies to our situation. Our question asks which "does not" apply
awh man:(
b
Not B
You need to evaluate each situation and see which will not give you an outcome of 0.
If Tony pulls 2A (twice as hard) as Ralph 1B then they will not move(0)
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