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Mathematics 19 Online
OpenStudy (anonymous):

Which of the following situations cannot be modeled with the equation 2x + y = 0? A. It takes 2 parts of chemical A to neutralize 1 part of chemical B. B. Tony must pull twice as hard as Ralph just to sit still in a match of tug-o-war. C. If Sophie earns twice as many points as penalties, she will break even. D. Tom’s Saturday shift was twice as long as his 2 hour Sunday shift.

OpenStudy (anonymous):

@mathstudent55

OpenStudy (anonymous):

@LoveAlwaysKayla

OpenStudy (anonymous):

@Johnbc

OpenStudy (anonymous):

As you can see your expression is equal to 0 so you must see which one of your situations does not equal 0.

OpenStudy (anonymous):

is it c

OpenStudy (anonymous):

If Sophie earns 2 x points as Penalties she will "break even" if we set points as A and penalties as B and breaking even as 0. 2A+1B = 0 so it does apply

OpenStudy (anonymous):

so i was right!?(:

OpenStudy (anonymous):

thank you thank you!

OpenStudy (anonymous):

No it was not C

OpenStudy (anonymous):

C applies to our situation. Our question asks which "does not" apply

OpenStudy (anonymous):

awh man:(

OpenStudy (anonymous):

b

OpenStudy (anonymous):

Not B

OpenStudy (anonymous):

You need to evaluate each situation and see which will not give you an outcome of 0.

OpenStudy (anonymous):

If Tony pulls 2A (twice as hard) as Ralph 1B then they will not move(0)

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