Which function below is the inverse of f(x) = The quantity of two x plus three, over five.? f−1(x) = The quantity of five x plus three, over two f−1(x) = The quantity of five x minus three, over two f−1(x) = Five over the quantity of two x plus three f−1(x) = Five over the quantity of three minus two x
\(y=\frac{2x+3}{5}\) can you solve this for \(x\)?
5-3/2x?
I dont know what that is....use parentheses
but it does not look right
y=(5-3)/(2x)
\(y=\frac{2x+3}{5}\) multiply both sides by \(5\) \(5y=2x+3\) subtract 3 \(5y-3=2x\) divide by 2 \(\frac{5y-3}{2}=x\)
now "flip" the \(x\) and \(y\). \(f^{-1}(x)=y=\frac{5x-3}{2}\)
Some people like to "flip" the \(x\) and \(y\) first, then solve for \(y\). But its all the same thing...
so i just solve for x and then flip the x and y ?
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