Can someone explain problem 6 on Driven RLC Circuits for me? I think Professor Lewin is wrong. The circuit is not in resonance; therefore how could omega = 1/(square root of LC)?
Here is the link: http://ocw.mit.edu/courses/physics/8-02sc-physics-ii-electricity-and-magnetism-fall-2010/oscillating-circuits/driven-rlc-circuits/
Thanks a lot :D

Question

radar · Answer

The circuit is resonant only to the desired frequency, the lower frequency the circuit presents an impedance (as the capacitance reactance will exceed the inductive reactance.  I think the professor overall did a good job on the explanation. (except for alluding that R was the resistance associated with the speaker).  He did make some assumptions for convenience in the solution, I think assuming that v (sub 0) of both signals were equal even though the power of  one was less than the other, then manipulating the current to establish the power ratio, afterall it was his chalk.

masumanwar · Answer

rlc circuit is connected resistance, inductor , capacitor in a circuit with a current supply can go under damping oscillation

masumanwar · Answer

and can happen under damp over damp depending on resistance and if resistance is zero it will become lc oscillator where charging in the electric and magnetic field will oscillate

masumanwar · Answer

and we need to solve the differential equation for this

masumanwar · Answer

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