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Mathematics 10 Online
OpenStudy (anonymous):

T he equation for a parabola with directrix y = –p and focus (0, p) is: https://media.glynlyon.com/g_alg02_ccss_2013/8/equation_parabola.gif What is the line of symmetry? x-axis y-axis x = p x = -p

OpenStudy (anonymous):

y = .....x^2 is an upward parabola which has y-axis is the line of symmetry.

OpenStudy (anonymous):

y-axis was my 1st answer but it was incorrect

OpenStudy (anonymous):

so, it's over my head. I am sorry for being helpless. :) Let tag other @SithsAndGiggles

OpenStudy (anonymous):

The directrix is horizontal, so the axis of symmetry (which is always perpendicular to the directrix) is vertical. Any vertical line has the form \(x=\cdots\). The axis of symmetry must pass through the vertex and focus. If this axis is the line \(x=\cdots\), then \(\cdots\) is the x-coordinate of any point on this line. You know one point that lies on the line. What's its x-coordinate?

OpenStudy (anonymous):

x=p

OpenStudy (anonymous):

No, what's the x-coordinate of (0,p)?

OpenStudy (anonymous):

sorry about that, my mouse wasn't working so I couldn't send my message. x-axis @SithsAndGiggles

OpenStudy (anonymous):

No, it's the y-axis. The y-axis has the equation \(x=0\).

OpenStudy (anonymous):

It says it's incorrect

OpenStudy (anonymous):

can you copy the page and paste it here??

OpenStudy (anonymous):

|dw:1403800844268:dw|

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