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Simplify (sin theta- cos theta)^2+(sin theta +cos theta)^2 A 1 B 2 C sin^2 theta D cos ^2 theta
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FOIL
Its been a while since ive done that, and was always bad at it, mind helping?
\(sin\theta-cos\theta)^2=(sin\theta-cos\theta)*(sin\theta-cos\theta)\)
so the answer would just be 1?
why?? just apply \((a\pm b)^2= a^2 \pm 2ab +b^2\) and then simplify, don't guess, work and you get the answer, it is not 1
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I was thinking it was one because the two sides would cross each other out, but give me a second and ill do it your way :D
Alright i lied, i have no idea how to do that.
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