What is the inverse of the given function? y = 7x2 - 3.
\(y=7x^2-3\) can you solve for \(x\)
we cant open those links....
And how do i solve for x?
they ask for user/pass
All of them?
yes
Well just forget them lol So how do i do this ?
\(y=7x^2-3\) add 3 to both sides \(y+3=7x^2\) divide by 7 \(\frac{y+3}{7}=x^2\) square root both sides \(\pm\sqrt\frac{y+3}{7}=x\)
now switch the \(x's\) and \(y's\) \(y=\pm\sqrt{\frac{x+3}{7}}\)
note that this is not a function
Umm thanks ? :)
lol whats the ? for?
Cause you kinda did the problem for me /.\ I mean thanks like so much :) but i wanted to like ...do it lol in case i get a problem like it again
so i know how to solve it:P
lol I showed you how to do it,
I showed each step and explain each step, if you don't understand a part, ask about it. Else do the same thing....
its the same thing if i said 7=3x+8 and asked you to solve for x just now you have a y in there, but thats ok .... just treat it like a number
ok:)
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