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Mathematics 20 Online
OpenStudy (dumbsearch2):

Determine which of the following is a solution to y > -x2 + 4x - 6 by graphing. A. (0, -6) B. (0, 0) C. (2, -3) D. (3, -4)

OpenStudy (dumbsearch2):

Just guide me through :) I despise cheating. Thanks in advance for everyone's help!

Parth (parthkohli):

Are you sure you need graphing for this? There's a way to do it without that, but alright, let's do it the graph way.

OpenStudy (dumbsearch2):

It doesn't ask for any graph, no.

Parth (parthkohli):

Then you can try and plug in each and every choice, and then check if the inequality holds true.

OpenStudy (anonymous):

\[ y > -x^2 + 4x - 6 \]For \((0,-6)\) we put: \[ -6 > -(0)^2 + 4(0) - 6 \\ -6 > 0 +0 - 6 \\ -6 > -6 \]False, so \((0,-6)\) doesn't work.

Parth (parthkohli):

^ Did you follow that? Could you extend it to other choices as well?

OpenStudy (dumbsearch2):

Gotcha

OpenStudy (dumbsearch2):

Thank you. Understood! I'll try this and tell you if I need more help.

OpenStudy (dumbsearch2):

So to check D, would I do \[−3>−(2)^2+4(2)−3\]

OpenStudy (dumbsearch2):

I meant C. C. (2, -3)

Parth (parthkohli):

Yes, that step is correct.

OpenStudy (dumbsearch2):

Oh dear. I got false on all accounts.

Parth (parthkohli):

I see. Double-checked, and you seem to be correct.

OpenStudy (dumbsearch2):

C and D didn't work. Let me try B.

Parth (parthkohli):

Oh, I forgot to try B myself. lol

OpenStudy (dumbsearch2):

Shucks, again false.

Parth (parthkohli):

Why?

Parth (parthkohli):

\[0 >-6\]

OpenStudy (dumbsearch2):

No it's TRUE! Gosh I did it wrong haha

OpenStudy (dumbsearch2):

Thank you, I suppose B is the answer.

Parth (parthkohli):

Yup, it should be.

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