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Mathematics 7 Online
OpenStudy (anonymous):

No clue. Vector ST is shown in the coordinate plane below. What is the component form of Vector ST ? A. <–4, 9> B. <–4, –9> C. <4, 9> D. <4, –9> @jim_thompson5910 @shinebrightlikeadimon @satellite73

OpenStudy (anonymous):

OpenStudy (anonymous):

sorry no clue either

OpenStudy (anonymous):

:(

OpenStudy (anonymous):

i am going to make a guess at A \(<-4,9>\)

OpenStudy (anonymous):

think of moving the point \(T\) to the origin that would move it left 2 and up 5

OpenStudy (anonymous):

guess i meant "up 4"

OpenStudy (agent0smith):

To get from S to T, you go left 4, and up 9 left 4 means -4 is the x-value up 9 means +9 is the y-value

jimthompson5910 (jim_thompson5910):

Two ways to look at it A) you start at (2,-4) and you need to get to (-2,5). So you go 4 units to the left and 9 units up. This is represented by the vector <-4,9> B) subtract the corresponding components (tail - head) to get x: -2-2 = -4 y: 5 - (-4) = 9 so again, we get the vector <-4, 9>

OpenStudy (anonymous):

lol no

OpenStudy (agent0smith):

I like how he put it in all caps, so sure of himself.

OpenStudy (anonymous):

Thank you all ; so many bright minds :) HAha- @agent0smith ; yes, I saw that..

OpenStudy (anonymous):

ans A

OpenStudy (agent0smith):

Welcome, @lilia222

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