Question

f(x)=1/x and g(x)=x^2-4x two numbers are not in the domain of f°g

Answer 1

\[f\circ g(x)=f(g(x))=f(x^2-4x)=\frac{1}{x^2-4x}\]

Answer 2

since you cannot divide by zero, the two numbers you are looking for are the solutions to
\[x^2-4x=0\]

Answer 3

@satellite73 that is wrong

Answer 4

what is wrong?

Answer 5

the answer

Answer 6

what answer?

Answer 7

idk im confused

Answer 8

can you help @satellite73

Answer 9

i found out its (4,0)

Answer 10

@satellite73 thank you